.Begin Table C.

Modelling                                              113

Diode Modelling                                        115

Diode                                                  115

Diode Operating Characteristic                         116

Small Single Diode                                     118

Small Signal Diode Model                               119

High Frequency Small Signal Diode Model                121

BJT Modelling                                          123

Idealized Cross Section of NPN BJT                     123

Bipolar Junction Transistor Small Signal Model         124

Summary of Capacitive Considerations                   125

Transistor Models                                      125

Summary of BJT Models                                  126

Low Frequency (LF) Small Signal Models                 126

Small Signal BJT                                       126

BJT Models                                             129

Using the r Parameter Model                            130

Effect of an AC Load                                   133

h Parameter BJT Model                                  134

CE h Parameter Determination Using Characteristics     136

h to r Parameter Conversion                            136

Analysis using the Hybrid h Parameter Model            139

Hybrid p Model of BJT                                  140

Determination of Hybrid p Parameters                   141

Analysis using the Hybrid p Model                      142

Use of Small Signal Transistor Models                  144

Justification for Using Approximate Circuits           145

Bode Magnitude and Phase Plots                         146

Transfer Functions                                     147

Cascaded Amplifiers                                    147

High Pass Filter (Series Capacitor)                    148

High Pass Filter Response                              150

Low Pass Filter (Shunt Capacitor)                      151

Low Pass Filter Step Response                          153

General Frequency Effects (BJTs)                       155

Selection of Corner Frequency                          160

Phase Response Overview (CE)                           162

Effect of Zeros                                        162

Stray Effects                                          163

Broadbanding                                           164

Shunt Peaking                                          165

Multiple Stage Consideration (Identical Stages)        166

Design                                                 172

Requirements of a Designer                             173

The Design Process                                     174

Design Procedure for Simple BJT Amplifier              174

Amplifier Testing                                      175

Electronic Computer Aided Design (ECAD)                176

Usefulness of Computer-Aided Design                    176

SPICE                                                  180

PSPICE Overview                                        183

Special Setup for CAD Lab F211                         184

PSPICE BJT Model                                       185

Guidelines for Using Simulator (EG. SPICE)             186

PSPICE Example                                         187

Computer Models of BJTs                                191

Non-Linear Hybrid p Model                              192

AC Ebers-Moll Model                                    193

Small Signal Hybrid p Model                            196

Gummel-Poon (G-P) Model                                197

Modelling the Low Current Gain                         199

Forward Transit Time tF                                200

SPICE BJT Model                                        202

SPICE 2G Bipolar Transistor Model Parameters           204

SPICE Model of the Bipolar Transistor                  205

FET Modelling                                          206

Small Signal JFET                                      207

JFET Transconductance                                  207

Small Signal E MOSFET                                  208

Small Signal FET                                       209

FET Model (CS)                                         209

Common Source FET Amplifier                            212

General Frequency Effects (FETs)                       215

Maximum Operating, or cut off, Frequency for FETs      215

General Amplifier Transfer Function                    216

Low Frequency General Form                             217

High Frequency General Form                            217

Low Frequency Response of a BJT Amplifier              218

Low Frequency Cut off Frequency                        221

High Frequency Analysis of Common Emitter BJT          222

High Frequency Analysis Using Miller's Theorem         225

Low Frequency Response of a FET Amplifier              226

High Frequency Response of a FET Amplifier             228

Frequency Response Analysis Using Time Constants       229

Resume of High Pass and Low Pass Corner Frequencies    229

Effect of Emitter By-Pass Capacitor                    230

Effect of Input Coupling Capacitor                     231

Effect of Output Coupling Capacitor                    232

High Frequency Effect of Input Circuit                 233

High Frequency Effect of Output Circuit                234

High Frequency Effect of Miller Input Capacitance      234

Common Collector Amplifier                             235

Common Base Amplifier                                  237

Other Transistor Configurations                        239

Phase Splitter                                         239

Bootstrap Technique (BJT)                              240

Bootstrapping the FET                                  241

Transistor Circuit Noise                               243

.End Table C.


Modelling

 

Passive (R, L, C) versus Active (BJT, FET, etc.)

 

  Resistance  - current flow leads to magnetic field effect

                (model as series LR).

              - voltage difference leads to electric field

                effect (model as parallel CR).

 

 

  Inductance  - winding resistance leads to RL.

              - capacitance between turns leads to CL.

 

 

  Capacitance - leakage current through dielectric leads to

                RC.

              - inductance of leads and plates leads to LC

 

 

ZE(R)=R, ZE(L)=jwL, ZE(C)=1/(jwC)

 

Therefore, devices are only simple under limited conditions outside this range parasitics must be accounted for.

We have frequency effects as above but also nonlinearity effects e.g. bulbs, diodes etc.

Therefore, to model one must specify operating conditions and amplitude of voltage and current excursions.

 

Two possible forms of models:

 

 (1) small signal model - Looking at small signal variations

                          about Q.

 (2) large signal/total - Looking at complete situation.

 


Diode Modelling

 

Diode

 

 


Diode Operating Characteristic

 

 

                       vD        

         iD = IS (exp ----- - 1) 

                       nVT       

where

     VT = KT/q = 25mV at room temperature.

     K = Boltzmann's constant 1.38 x 10-23 J/K

     T = Absolute temperature (K) = 273 + oC

     q = electron charge 1.602 x 10-19 C

     n = device constant between 1 and 2

 

For IC n=1, and for discrete (high or low current) n=2.

IS = reverse current (doubles for every 5o increase in temperature.)

 

                               vD

In forward bias  iD » IS exp -----

                              nVT

 

In reverse bias  iD » - IS.

 


 

 

 

 

 

 

 

 

 

 

 


Small Single Diode

 

 

 

                  VD/nVT

DC       ID = IS e

 

                                              vD/nvT

Instantaneous  vD = VD + vd    and   iD = IS e

 

             (VD+vd)/nVT         vD/nVT   vd/nVT

\   iD = IS e             =  IS e        e

 

Substitute for ID

 

              vd/nVT

     iD = ID e

 

If vd is kept small so that vd/nVT<<1 we can use a series expansion and retain first two terms

 

 \   iD » ID(1 + vd/nVT)

 

N.B. general requirement for small signal behaviour is that second order terms and above in the series expansion are negligible.

That is

 

      vd       1     vd   

     ----- >> --- ( ----- )2

      nVT      2!    nVT 

 

 \   2nVT >> vd

 

Assume n = 1 and VT = 25mV

We require vd << 50mV

i.e. vd of the order of 5mV or so.

 

                ID

 \   iD = ID + ----- vd = ID + id    - DC + AC component

                nVT

 

           ID

     id = ----- vd = gdvd = vd/rd

           nVT

 

where gd is the small signal diode conductance.

      rd = 1/gd is the small signal diode resistance or

          incremental resistance

 

                   25

N.B.  rd º re = ---------

                 ID (mA)

 

 

Small Signal Diode Model

 

     Replace diode's nonlinearities by a Taylor's series expansion around Q and only retain the linear part.

 

          vD = VQ + vd

 

          iD = IQ + id

 

 

Taylor's series about x = a is

 

                    df ¦           1   d2f ¦

     f(x) = f(x) + ----¦  (x-a) + --- -----¦   (x-a)2 + ....

                    dx ¦x=a        2   dx2 ¦x=a

 

For x near "a" (¦x-a¦<<1) non linear terms can be ignored.

 

 

 

Therefore,  for the diode

 

               ¦     df  ¦

     iD = f(vD)¦  + -----¦ (vD - VQ) + nonlinear terms

               ¦Q    dvD ¦Q

 

                    vD

where  iD » IS exp -----

                    VT

 

                  VQ       1          VQ   

 \   iD = IS exp ---- + ( --- IS exp ---- ) vd + ....

                  VT       VT         VT  

                     

 

for vd very small

 

                       IQ 

     IQ + id » IQ + ( ---- ) vd

                       VT 

 

           IQ

 \   id = ----  vd

           VT

 

           vd      25

 \   rd = ---- = -------

           id     IQ(mA)

 


High Frequency Small Signal Diode Model

[S & S P157]

 

Includes capacitive effects

 

(1) Reverse bias - capacitor CJ  due to the wide depletion layer

 

 

 

                dqJ

          CJ = ----- _

                dv    v=VA

 

                    K

          CJ = -----------

                (V0 + VA)m

 

                   CJ0

             » ------------

                (1+VA/V0)m

 

where

 

     V0 = depletion layer voltage with zero bias

     VA = voltage between diode terminals

     K  = constant proportional to area of junction and

          impurity concentration.

     m  = constant proportional to distribution of impurity

          near junction.

     (m = 1/2 for abrupt junction

       = 1/3 for gradual junction [B&B P63]).

 

N.B. VA is negative

 

(2) Forward bias - in addition to CJ we have CD which is due to minority charge storage

 

 

             25                K   

     rd = -------- ,  CJ = ----------- ,

           IQ(mA)           (V0+VA)m

 

     CD = KcIQ

 

           tFIDq

        = --------    [B&B P64]

            eKT

 

Kc = Constant

e empirical constant in diode equation º 1 to 2

 

N.B. VA is positive

 

[ CJ » 1-5pF, rd » 106W, CD » 10-100pF]


BJT Modelling

 

Idealized Cross Section of NPN BJT

 

 


Bipolar Junction Transistor Small Signal Model

 

 


Summary of Capacitive Considerations

 

Capacitive effects generally attributable to:

 

 (1) Coupling and by-pass capacitors.

 (2) Internal device capacitances and strays.

 

For DC :-  f = 0

     open circuit (1) and ignore (2)

 

For LF :-  f less than a few 100Hz

     include (1) and ignore (2)

 

For MF :- a few 100Hz < f < a few 100KHz

     short circuit (1) and open circuit (2)

     use r, h parameter etc.

 

For HF :-  f greater than a few 100KHz

     short circuit (1) and include (2)

     use hybrid p for f <fT/3

 

N.B. for small signals:

 

    Replace independent DC voltage sources by short circuit.

    Replace independent DC current source by open circuit.

    Neglect strays if XC/R > 10 (see later).

 

 

Transistor Models

 

     Used to facilitate practical understanding and design.

2 main types:

 

     (1) small signal/linear - limited region of operation;

     (2) large signal/nonlinear - use straight line

                                linear segments.

 

Assumptions lead to trade off between complexity and

accuracy versus "useability" (computer versus manual calculations).

 

Frequency dependence therefore use a high or low frequency model as appropriate.

 

Examples of popular models include:

 

BJT - r parameter,  h parameter,  hybrid p,

FET - y parameter.

 


Summary of BJT Models

 

 DC :- Forward active.

       Simplified Ebers-Moll.

 

 

Small Signal - first order e.g. r parameter (LF & MF)

             - h parameter (LF & MF)

             - hybrid p parameter (LF, MF, & HF)

 

Complete models (small and large signal)

     Ebers-Moll  -+ used for computer

     Gummel-Poon -+ simulation

 

 

Low Frequency (LF) Small Signal Models

 

Assumptions :-

 

     (1) Transistor operating in linear region around

         operating point "Q".

     (2) Signal variations are small.

     (3) No distortion occurs.

 

 

Small Signal BJT

 

Forward biased base emitter junction

 

                                    vBE/VT

     vBE = VBE + vbe  and  iE = IS e

 

              (VBE+vbe)/VT        VBE/VT   vbe/VT

 \   iE = IS e              = IS e        e

 

               vbe/VT                  VBE/VT

         = IE e        where  IE = IS e

 

If vbe << VT then we can neglect second order terms from the series expansion (leads to linear operation).

 

 \   iE » IE (1+vbe/VT)

 

     VT » 25mV but this small signal approximation holds if vbe is less than about 10mV.

 

                 IE

 \   iE = IE + ------ vbe    - DC + AC component

                 VT

 

                    IE

AC component  ie = ----- vbe  = gmvbe

                    VT

 

gm is the transconductance   IE/VT (= 1/re)

 

N.B.  BJT :-  gm depends on IE and VT.

      FET :-  gm depends on Ö(ID) and W/L.

 

 

Base Input Resistance rp (first order model)

 

We have

                      IC       

      iC » iE = IC + ---- vbe 

                      VT      

 

           IC     IC

     iB = ---- + ----- vbe

           b      bVT

 

 \   iB = IB + ib

 

            1   IC

i.e.  ib = --- ---- vbe    but   gm » IC/VT

            b   VT

 

           gm

\    ib = ---- vbe

           b

 

Input resistance rp = vbe/ib = b/gm

 

substitute for gm  and  IB = IC/b

 

     rp = VT/IB

 

                    ¦¦¦

 

First order models apply to both npn and pnp without change in polarities.

 

     vbe = vp

 

Since output current is gmvp = gm rp ib = b ib

 

 

Emitter Resistor re (first order model)

 

     iE = iC / Á = IE + ie

 

                                  IC          IE

 where  IE = IC / Á   and   ie = ----- vbe = ----- vbe

                                  ÁVT         VT

 

              vbe     VT

 but    re = ----- = ----

              ie      IE

 

              IE     IC

        gm = ---- » ----

              VT     VT

 

 \      re » 1/gm

 

re is base emitter resistance when looking in at e.

rp is base emitter resistance when looking in at b.

 

 

 

 [It can be shown that  rp = (b+1)re ]


BJT Models

 

     Equivalent Tee (T) or r parameter

 

 

     Represents a CE amplifier biased in the forward active     region (base emitter junction forward biased and base     collector junction reverse biased).

 

Whence:-

 

            25

     re= -------- ;  resistance of forward biased junction.

          IE(mA)     (room temperature 300K)

 

     rc - large resistance of reverse biased junction.

     rb - base spreading resistance.

     ic = Á0ie » b ib

 

where Á0 is LF current gain.

 

           b              1+hfe

     Á = ------     rc = -------

          1+b              hoe

 

           hre                       hre(1+hfe)

     re = -----    and   rb = hie - ------------

           hoe                          hoe

 

Some typical values are:-

 

     re = 10 W

     rb = 100 W

     rc = 1 M W

     Á0=  0.99

 

rb and rc can often be omitted.

 


Using the r Parameter Model

 

     Consider the potential divider emitter resistor circuit shown below

 

 

(1) For DC design open circuit all capacitors.

 

 

 

(a) Ignoring R1 and R2 we have:

 

          Vin = VBE + VE = VBE + IERE

 

              = IERE     if VE>>VBE

 

Now  IE = IB(1+bdc) » bdcIB    if bdc>>1

 

                      Vin     IBbdcRE

  \       Rin(base)= ----- = ---------- = bdcRE

                      Iin       IB

 

(b) with R1 and R2

 

                   R2 __ Rin(base)

          VB = ---------------------- VCC

                R1 + R2 __ Rin(base)

if    bdcRE>>R2 then

 

                 R2

          VB » ------- VCC

                R1+R2

 

Other components can be found by the use of KCL and KVL. For example:

 

          VE = IERE = VB-VBE

 

          VCE = VCC-IERE-ICRC

          etc.

 

Or use Thevenin's theorem where

 

                                     R2

          RT = R1 __ R2   and  VT = ------- VCC

                                    R1+R2

          VT = IBRT + VBE + VE

 

[circuit is independent of IE if RE>>RT/bdc]

 

N.B. used to calculate DC loadlines.

 

(2) For AC considerations short circuit all capacitors and replace the DC source by ground (assuming the internal resistance » 0)

 

N.B. without CE and RL

 

 

                         ¦¦¦

 

 

where R = R1 __ R2  (rb and rc are assumed to be negligible)

 

                      vb     ie (re+RE)

          Rin(base)= ---- » -----------  » b(re+RE)

                      ib      ie/b

 

          Rin = R __ Rin(base) = R1 __ R2 __ b(re+RE)

 

          Rout » RC   [if rc>>RC]

 

               vc         ieRC           RC

          Av= ---- » - ----------- » - -------

               vb       ie(re+RE)       re+RE

 

                ic

          Ai = ---- = b

                ib

 

Overall gain is reduced by potential divider effect i.e.

 

            vc       Rin      -RC            RC

     Avs = ----- = --------  -------   ( x ------- with RL)

            vs      Rs+Rin    re+RE         RC+RL

 

with emitter by pass capacitor CE:

 

(1)

 

     Open circuit to DC, therefore no effect

     Short circuit to AC, therefore Av=-RC/re

 

 

 

(2)

 

     DC bias sees RE1+RE2

     AC sees RE1 therefore Av=-RC/(RE1+re)   

 

(3)

 

     DC bias sees RE1

     AC sees RE1 __ RE2 therefore Av=-RC/((RE1 __ RE2) + re)

 

re(=25/IC(mA)) is temperature dependent, therefore it must be small in comparison with RE AC for good stability.

N.B. effect of CE on BW.

 

 

Effect of an AC Load

 

With CE

 

 

                RC __ RL

  \     Av » - ----------

                   re

 

N.B.  if RL>>RC Þ  RC __ RL » RC

      if RL<<RC  Þ  RC __ RL<RC (gain smaller with RL)


h Parameter BJT Model

[Nevan P237]

 

CE input characteristics leads to vBE = f(iB, vCE)

CE output characteristics leads to iC  = g(iB, vCE)

 

via a 2-D Taylor series about Q we obtain the linear approximation:-

 

            vBE            vBE

     vbe » ------ _ (ib) + ------ _ (vce)

            iB    Q        vCE   Q

                                         

           iC            iC

     ic » ----- _ (ib) + ------ _ (vce)

           iB   Q        vCE   Q

 

Two port theory leads to :-

 

     vbe = h11 ib + h12 vce

     ic  = h21 ib + h22 vce

 

where vbe and ic are dependent variables and vce and ib   are independent variables.

 

For CE amplifier

 

                  vbe            DvBE 

     h11 = hie = ----- _      » ------ _

                  ib    vce=0    DiB    VCEQ

 

                  vbe            DvBE 

     h12 = hre = ----- _      » ------ _

                  vce   ib=0     DvCE   IBQ

 

                  ic            DiC

     h21 = hfe = ---- _      » ------ _

                  ib   vce=0    DiB    VCEQ

 

                  ic             DiC

     h22 = hoe = ----- _      » ------ _

                  vce   ib=0     DvCE   IBQ

 

where hie is CE input resistance with output shorted,

      hre is CE voltage feedback ratio with input open,

      hfe is CE forward current gain with output shorted,

      hoe is CE output conductance with input open.

 

h parameters can be obtained from characteristic's from data sheets or practical measurements.

 

The model may often be simplified by omitting the effects of hre and hoe.

 

CE h Parameter Determination Using Characteristics

 

 


h to r Parameter Conversion

 

     It can be shown that

 

     re = hre/hoe

 

     rc = (hre+1)/hoe

 

                 hre

     rb = hie - ----- (1+hfe)

                 hoe

 

     b = hfe

 

                ic

     Á = hfb = ----

                ie


Example:

 

     How significant are hre and hoe in the circuit below?

VCC = 20V, RB = 2MW, RC = 5KW, hie = 2KW, hre = 10-4, 1/hoe = 100KW and hfe = 100.

 

- Effect of hoe

 

the effective collector resistance is RC'

 

     RC' = RC __ 1/hoe

 

For engineering purposes

 

     RC' » RC  if 1/hoe is greater about 10RC

 

This is easily the case

 

 \   RC' » RC = 5KW

 

Therefore, little error in neglecting hoe

 

- Effect of hre

 

     vce = icRC' = -hfeibRC'

 

\   hrevce = -(hrehfeRC') ib

This is dependent on ib. Using the source absorption theorem hrevce can be replaced by an equivalent resistance R

 

     R = hrehfeRC' = 50W

 

Therefore, since  hie (=2KW) >> 50W, effect of hre is negligible.

 

N.B. Generally hrevce can be replaced by a short circuit if    hre << hie/hfeRC'

 


Analysis using the Hybrid h Parameter Model

 

 

Medium frequencies, therefore ignore capacitors (short circuits).

Bias design with capacitors open circuit as before.

AC equivalent with R = R1 __ R2 and neglecting the effects of hoe and hre.

 

 

Voltage gain

 

     Vo = - hfeIb (RC __ RL)

 

     Vi = Ibhie + (1 + hfe)IbRE1

 

            Vo        -hfe (RC __ RL)

\    Avi = ---- = ----------------------

            Vi     (hie + (1 + hfe)RE1)

 

Current gain

 

                   RC

     Io = hfeIb ---------

                 RC + RL

 

     Vi = I1R = Ibhie + Ib (1 + hfe)RE1

Also     Ii = I1 + Ib

 

                        R          

\    Ib = Ii ------------------------

              R + hie + (1 + hfe)RE1

 

           Io                hfeRCR              

\    Ai = ---- = ------------------------------------

           Ii     (R + hie + (1 + hfe)RE1) (RC + RL)

 

Input impedance

 

By inspection Zin = R __ (hie + (1 + hfe)RE1)

 

Output impedance

 

(Set Vs = 0 and look into the output terminals)

 

     Ib = 0    \ hfeIb = 0     \  Zo = RC

 

 

Hybrid p Model of BJT

 

 

     By comparison with the h parameter model it can be shown that

 

                    rp

     hie = rb + ---------- » rb + rp

                 1 + rpgm

 

            rp(gm - gm)

     hfe = ------------- » rpgm

             1 + rpgm

             

               rpgm              

     hre = ----------- » rpgm » 0

            1 + rpgm

 

     hoe = go + gm + rpgm(gm - gm) » go + rpgmgm » go

 

(we have assumed that rpgm <<1,  gm<<gm  and gm<<go)

 

Rearranging the above

 

     rp = hfe/gm

 

     rb = hie - rp

 

     rm = rp/hre

 

     go = hoe - gmhre

 

               25      

     ( re = -------- = 1/gm ) 

             IC(mA) 

 

Another popular representation of the hybrid p model is shown below.

 

 

 

Determination of Hybrid p Parameters

 

            1      e

(1)  gm = ---- = ---- _ IC _

           re     KT

 

         » 40 _ IC _ at room temperature

 

(2)  b = hfe or hFE

 

(3)  rb'e = bo/gm

 

(4)  rbb'  is small and difficult to evaluate.

 

     If LF hie is known

 

          rbb' = hie - rb'e

 

     or if HF yie is known

 

          rbb' = 1/Real part (yie)

 

(5)  Cb'c is usually given as Cob, Cobo, Cc, Ccb etc.

 

                             gm    

(6)  If fT is known  Cb'e = ----  - Cb'c

                             wT

 

                                  1

     If fb is known  fb = --------------------

                           2prb'e(Cb'e + Cb'c)

     can be used.

 

 

Analysis using the Hybrid p Model

 

 

                           ¦¦¦

 

 

AC equivalent with R = R1 __ R2 and neglecting the effects of rb'c and rce.

 

At the three nodes we have

 

          VO(GC + GL) + gmVb'e = 0                     (1)

 

          VE = (Vb'e gb'e + Vb'e gm) RE1               (2)

          VI = Vb'e gb'e (rbb' + rb'e) + VE

 

             = Vb'e [rbb' gb'e + 1 + (gb'e + gm) RE1]  (3)

 

Voltage gain Avi

 

            VO                 -gm                       

     Avi = ---- = ------------------------------------    

            VI    [rbb'gb'e + 1 + (gb'e+gm)RE1][GC+GL]

 

                -gm             -RC __ RL

         » ------------------ » --------- 

            (1+gmRE1)[GC+GL]      RE1

 

          [if gmRE1>>1, rbb'<<rb'e and go<<GC+GL]

 

Input resistance

 

     Ib'e = Vb'e gb'e   and therefore using equation (3)

 

                      VIgb'e

          = -----------------------------

             rbb'gb'e + 1 + (gb'e+gm) RE1

 

                        VI

          = -----------------------------

             rbb' + rb'e + (1+gmrb'e)RE1

 

     II = VIG + Ib'e    where G = 1/R

 

                                1                 

 \   II = VI [ G + ----------------------------- ]

                    rbb' + rb'e + (1+gmrb'e)RE1 

 

But  b = gmrb'e

 

          VI      R[rbb' + rb'e + (1+gmrb'e)RE1]

\   Ri = ---- = ----------------------------------

          II     R + rbb' + rb'e + (1+gmrb'e)RE1

 

         = R __ [rb'e + (1+b)RE1]

 

Current gain Ai

 

           IO     VO   Ri           -gmGLR rb'e

     Ai = ---- = ---- ---- = -------------------------------

           II     VI   RL     (GC+GL)[R+rbb'+rb'e+(1+b)RE1]

 

If  rbb'<<rb'e  and  1<<gmrb'e

 

                -gmGLR rb'e

     Ai = --------------------------       

           (GC+GL)[R+rb'e(1+gmRE1)]

 

            -gm(RC __ RL)R rb'e

        =  ---------------------

              RL(R+rb'e+bRE1)

 

Output resistance

 

With rce omitted   Ro»RC

(Assuming rce << (GC + GL))

 

 

Including the effect of ro on voltage gain

[B&B P450]

 

 

     Vo(GC + GL + gce) = (gce - gm)Vb'e

 

     VE(GE + gce) = Vb'e(gb'e + gm) + gceVo

 

     Vi = Vb'egb'e(rbb' + rb'e) + VE

 

Combining all three equations

 

 Vo                  (gce-gm)(GE+gce)

----=-------------------------------------------------------

 Vi (GC+GL+gce)[(GE+gce)gb'e(rbb'+rb'e)+gb'e+gm]+gce(gce-gm)

 

gce can be neglected if gce<<(GC+GL) and gce<<GE and gce<<gm which is usually the case.

 


Use of Small Signal Transistor Models

 

(1) Mark B, C, E (or G, D, S) on the circuit diagram as the start of the equivalent circuit.

 

(2) Replace each Transistor by its model.

 

(3) Transfer all components (reisitors, capacitors and signal sources) to the equivalent circuit.

 

(4) We are only interested in changes around Q, therefore, replace each independent DC source by its internal resistance.

Ideal voltage source by short circuit and ideal current source by open circuit.

 

(5) Apply KVL and KCL as necessary.

 

Ro is defined with VS = 0 and RL = Ñ.

[Signal and load resistances should be included in the analysis as necessary.]

 

Justification for Using Approximate Circuits

[Comer]

 

     Inaccuracies can be shown to be quite small ( ~ 5 to 10%). Become even less important in the light of:

(1) Standard component tolerances of 5 to 20%, therefore values not accurately known.

 

(2) Most practical applications use an unbypassed or partially bypassed RE for good AC stability.

 

(3) 5 to 10% accuracy is good enough for most engineering design (?).  For better accuracy precision components are used in circuits that are designed to depend on component values rather than transistor parameters (feedback circuits).

 

(4) Greater accuracy can be achieved by additional elements, eg. reactive effects at high frequencies.

 

(5) Manual design work is limited by the complexity of more accurate models.

 

(6) Simpler circuits lead to a better physical feel and understanding of the dominant mechanisms.

 

(7) Transistor parameters required for more accurate models are not easily available from data sheets, and only typical values are usually provided.  Parameters vary widely so designers would need to measure them for each device.

Therefore,  its easier (?) to use simple models in feedback configurations with accurate resistors etc.


Bode Magnitude and Phase Plots

 

Decibel

 

 

Power gain

 

           P2    ¦ V2I2 ¦

     AP = ---- = ¦------¦ = Av Ai

           P1    ¦ V1I1 ¦

 

     AP(dB) = 10 log10 (P2/P1)

 

                        V22R1

            = 10 log10 -------

                        V12R2

 

            = 20 log10 ¦ V2/V1 ¦ + 10 log10 ¦R1/R2¦  

 

     AP(dB) = 20 log10 ¦ V2/V1 ¦     (if R1=R2)

                                  

            = 20 log10 ¦ I2/I1 ¦     (if R1=R2)

 

\    Av(dB) = 20log10 ¦ V2/V1¦

 

Notes -  0dB is often used as a reference

 

      -  half power condition - the frequency at which

         Ap = Apm/2

 

i.e.     Ap(dB) = 10log10 (0.5) = -3dB

 

         this is the same frequency as that at which

         Av = 0.707 Avm

 

i.e.     Av(dB) = 20log10 (0.707)= -3dB

 

       - dBm  decibels relative to 1mW 

 

i.e.      1mW = 0dBm.

 

(e.g. 2mW power  = +3dBm

      0.5mW power  = -3dBm).


Transfer Functions

 

Consider a network of the form shown below:

 

 

The transfer function for the network can be defined as follows:

 

              V2

     H(jw) = ----  (jw)

              V1

or

             V2

     H(S) = ----   (S)      [S=s+jw]

             V1

 

 

Cascaded Amplifiers

 

 

                             j(q1+q2+q3+ ... +qn)

     Av = ¦A1 A2 A3 ... An¦ e

 

\    Av(dB) = 20log¦A1¦ + 20log¦A2¦ + ... + 20log¦An¦

 

     qv = q1 + q2 + q3 + ... + qn

 


High Pass Filter (Series Capacitor)

[Bogart P370]

 

 

              V2             1

     H(jw) = ---- (jw) = ----------   [wc = 1/RC]

              V1          1-jwc/w

 

            1

\    fc = ------

           2pRC

 

                       1

\    ¦ H(jw)¦ = --------------

                 Ö(1+(wc/w)2)

 

     qL(jw) = tan-1 (wc/w)

 

 

Magnitude Response

 

 

Phase Response

 


                              1

Exact response for H(jw) = --------- 

                            1-jwc/w

 

 

          20log[1+(wc/w)2]-1/2      q(jw)=tan-1(wc/w)

  w               (dB)                    (degree)

 ------------------------------------------------------

  0               -Ñ                       90.0

  0.1wc           -20.04                   84.3

  0.5wc           -6.99                    63.4

  wc              -3.01                    45.0

  5wc             -0.17                    11.3

  10wc            -0.0432                  5.7

  Ñ                0                       0

 

 

[Bogart P370]

More generally for a circuit with

 

     Source resistance rs

     Input resistance ri

     Input series capacitance Cis

     Load resistance rL

     Output resistance ro

     Output series capacitance Cos

 

Then corner frequency due to Cis is

 

                  1

     fCis = --------------

             2pCis(rs+ri)

 

Corner frequency due to Cos is

 

                  1

     fCos = --------------

             2pCos(ro+rL)

 


High Pass Filter Response

 

 

 

[Millman P385]

N.B.

      t = RC

 

     fL =  % sag * fp/p

 

where fp is frequency of the pulse waveform.

 


Low Pass Filter (Shunt Capacitor)

 

 

              V2             1

     H(jw) = ---- (jw) = ---------   [wc = 1/RC]

              V1          1+jw/wc

 

            1

\    fc = ------

           2pRC

 

                      1

\    ¦ H(jw)¦ = --------------

                 Ö(1+(w/wc)2)

 

     qH(jw) = -tan-1 (w/wc)

 

 

Magnitude Response

 

 

 

Phase Response

 


                               1

 Exact response for H(jw) = --------- 

                             1+jw/wc

 

 

          20log[1+(w/wc)2]-1/2      q(jw)=-tan-1(w/wc)

  w               (dB)                   (degree)

 ------------------------------------------------------

  0                0                        0

  0.1wc           -0.0432                  -5.7

  0.5wc           -0.969                   -26.6

  wc              -3.01                    -45.0

  5wc             -14.15                   -78.7

  10wc            -20.04                   -84.3

  Ñ               -Ñ                       -90.0

 

 

More generally for a circuit with

 

     Source resistance rs

     Input resistance ri

     Input shunt capacitance Cip

     Load resistance rL

     Output resistance ro

     Output shunt capacitance Cop

 

Then corner frequency due to Cip is

 

                    1

     fCip = -----------------

             2pCip(rs __ ri)

 

Corner frequency due to Cop is

 

                    1

     fCop = -----------------

             2pCop(ro __ rL)

 


Low Pass Filter Step Response

 

 

 

N.B.      t = RC


Proof that fH = 0.35/tr

 

tr is the time required for a voltage to rise from 10% to 90% of its final value VF.  Where v is given by

 

     v = VF(1-exp(-t/(RC)))

 

when v = 0.1VF

 

     0.1VF = VF(1-exp(-t/(RC)))

     0.9 = exp(-t/RC)

     ln [exp(-t/(RC))] = ln 0.9

 

 \   t = 0.1RC

 

Similar analysis with v = 0.9VF gives

 

     t = 2.3RC

 

 \   tr = 2.3RC - 0.1RC = 2.2RC

 

Critical frequency for RC network is RC = 1/2pfH

 

           2.2      0.35

 \   tr = ------ = ------

           2pfH      fH

 

N.B.

(1) Corner frequency found in both cases by substituting

 

          ¦ H(jw) ¦ = 1/Ö2

 

(2) Overall multiple stage (section) response is determined by adding in the effect of the individuals.

 

(3) Special care must be exercised at break/corner frequencies wc, 10wc and wc/10 for each stage (section).

 

(4) Gain falls at 20dB/dec at wc

    phase falls at 45o/dec at 0.1wc

 


General Frequency Effects (BJTs)

 

(1) Low frequencies - ignoring HFs. 

 

    High-pass filter effects due to:

 

    - input coupling capacitance CI

    - output coupling capacitance CO

    - emitter by-pass capacitance CE (if present).

 

 

                   1

     fCIL= ------------------   rin'» R1 __ R2 __ bre

           2p(rin' + rs')CIL

 

                 1

     fCOL= ----------------     ro'= rce __ RC » RC

           2p(ro'+ RL)COL

 

             1                        rs' __ R

     fCE= -------         Re=RE __ [ ---------- + re ]

           2pReCE                        b

 

     (Am» -gm(RC __ RL))      (R= R1 __ R2)

 

 

(2) High frequencies - ignoring LFs.

 

    Low-pass filter effects due to:

 

      shunt capacitances to ground; wiring; solder joints;

      coupling from other devices; internal transistor

      capacitances.

 

 

                   1

     fCIH= --------------------  CIH=CWLI+Cb'e+Cb'c(1-Am)

            2p(rs' __ rin')CIH

                                  rin'» R1 __ R2 __ bRe

 

                  1

     fCOH= -------------------   COH= CWLO + Cb'C

            2p(ro' __ RL) COH 

                                  ro'= rce __ RC (»RC)

                            

                                  Am» -gm(RC __ RL)

 

 

(3) High frequency effect due to unity gain frequency fT

[B&B P493]

 

Unity Gain Frequency fT is used to characterise a transistor's frequency capability. fT is obtained using a circuit of the form:

 

 

                           ¦¦¦

 

rbb' and rb'c have been neglected.

 

     Vb'e = Is (rb'e __  XC    __  XC   )

                          b'e       b'c

 

                          1

              rb'e ( --------------- )

                     jw(Cb'e+Cb'c)       

          = ----------------------------- Is

                           1

              rb'e + ---------------

                      jw(Cb'e+Cb'c)

 

                     rb'e

          = -------------------------- Is

             1 + jwrb'e(Cb'e + Cb'c)

                                 

If we neglect the forward current through Cb'c

 

     Io » gm Vb'e

 

Using this along with  b0 = gm rb'e

 

      Io                        gm rb'e

     ---- (jw) = b(jw) = -----------------------

      Is                  1 + jwrb'e(Cb'e+Cb'c)

 

                            b0

              = -------------------------

                  1 + jw(Cb'e+Cb'c)b0/gm

 

 

We can best understand this by considering the following plot of CE and CB gains for short circuit output.

 

 

     wT » b0wb   or  fT = b0fb

 

Gain bandwidth product fT = b0fb

 

Therefore, the LF asymptote is b0 and the 3dB corner frequency is

 

                             gm     

     wc = wb = 2pfb = -----------------

                       b0(Cb'e + Cb'c)

 

 (wb is the b cut off frequency)

 

By setting ¦b(jw)¦ = 1  we obtain the unity gain frequency

 

                      gm              gm

     wT = 2pfT = --------------- = ---------

                  (Cb'e + Cb'c)     (Cp+Cm)

 


Typical Variations of fT Versus IE and VCE

 

 

Illustration of Capacitance Effects on Frequency Response

 

 


Response Curve Illustrating Bandwidth

 

 

 

Simplified Response Curve

 

Where fol is negligible compared to foh

 

 

 

Selection of Corner Frequency

 

Interaction or not?

 

LF:- Low frequency options using fCE to dominate

 

     - fCE=fL, fCI=fL/10, fCO=fL/100

 

          - 20dB/dec each.

 

     - fCE=fL, fCI=fCO=fL/10

 

          - 20dB/dec at fCE

 

          - 40dB/dec at fCI

 

     - fCE=fCI=fCO=fL

 

          - 60 dB/dec at fCE

 

     - fC=(fCE2+fCI2+fCO2)1/2

 

fCE used because it results in smaller values of capacitance.

 

 

HF:-  Less control but may use RS, RC, RL, Rin etc.

      Effect of wT.

 


Phase Response Overview (CE)

[M&M]

 

LF : contribution of up to 90o for each of the poles due to CIL, COL and CE if they are present.

 

Midband : phase shift should be 180o