Modelling 113
Diode Modelling 115
Diode 115
Diode Operating Characteristic 116
Small Single Diode 118
Small Signal Diode Model 119
High Frequency Small Signal Diode Model 121
BJT Modelling 123
Idealized Cross Section of NPN BJT 123
Bipolar Junction Transistor Small Signal Model 124
Summary of Capacitive Considerations 125
Transistor Models 125
Summary of BJT Models 126
Low Frequency (LF) Small Signal Models 126
Small Signal BJT 126
BJT Models 129
Using the r Parameter Model 130
Effect of an AC Load 133
h Parameter BJT Model 134
CE h Parameter Determination Using Characteristics 136
h to r Parameter Conversion 136
Analysis using the Hybrid h Parameter Model 139
Hybrid p
Model of BJT 140
Determination of Hybrid p Parameters 141
Analysis using the Hybrid p Model 142
Use of Small Signal Transistor Models 144
Justification for Using Approximate Circuits 145
Bode Magnitude and Phase Plots 146
Transfer Functions 147
Cascaded Amplifiers 147
High Pass Filter (Series Capacitor) 148
High Pass Filter Response 150
Low Pass Filter (Shunt Capacitor) 151
Low Pass Filter Step Response 153
General Frequency Effects (BJTs) 155
Selection of Corner Frequency 160
Phase Response Overview (CE) 162
Effect of Zeros 162
Stray Effects 163
Broadbanding 164
Shunt Peaking 165
Multiple Stage Consideration (Identical Stages) 166
Design 172
Requirements of a Designer 173
The Design Process 174
Design Procedure for Simple BJT Amplifier 174
Amplifier Testing 175
Electronic Computer Aided Design (ECAD) 176
Usefulness of Computer-Aided Design 176
SPICE 180
PSPICE Overview 183
Special Setup for CAD Lab F211 184
PSPICE BJT Model 185
Guidelines for Using Simulator (EG. SPICE) 186
PSPICE Example 187
Computer Models of BJTs 191
Non-Linear Hybrid p Model 192
AC Ebers-Moll Model 193
Small Signal Hybrid p Model 196
Gummel-Poon (G-P) Model 197
Modelling the Low Current Gain 199
Forward Transit Time tF 200
SPICE BJT Model 202
SPICE 2G Bipolar Transistor Model Parameters 204
SPICE Model of the Bipolar Transistor 205
FET Modelling 206
Small Signal JFET 207
JFET Transconductance 207
Small Signal E MOSFET 208
Small Signal FET 209
FET Model (CS) 209
Common Source FET Amplifier 212
General Frequency Effects (FETs) 215
Maximum Operating, or cut off, Frequency for FETs 215
General Amplifier Transfer Function 216
Low Frequency General Form 217
High Frequency General Form 217
Low Frequency Response of a BJT Amplifier 218
Low Frequency Cut off Frequency 221
High Frequency Analysis of Common Emitter BJT 222
High Frequency Analysis Using Miller's Theorem 225
Low Frequency Response of a FET Amplifier 226
High Frequency Response of a FET Amplifier 228
Frequency Response Analysis Using Time Constants 229
Resume of High Pass and Low Pass Corner Frequencies 229
Effect of Emitter By-Pass Capacitor 230
Effect of Input Coupling Capacitor 231
Effect of Output Coupling Capacitor 232
High Frequency Effect of Input Circuit 233
High Frequency Effect of Output Circuit 234
High Frequency Effect of Miller Input Capacitance 234
Common Collector Amplifier 235
Common Base Amplifier 237
Other Transistor Configurations 239
Phase Splitter 239
Bootstrap Technique (BJT) 240
Bootstrapping the FET 241
Transistor Circuit Noise 243
Modelling
Passive (R, L, C) versus Active
(BJT, FET, etc.)
Resistance - current flow leads
to magnetic field effect
(model as series LR).
- voltage difference leads to electric
field
effect (model as parallel CR).

Inductance - winding resistance
leads to RL.
- capacitance between turns leads to CL.

Capacitance - leakage current through dielectric leads to
RC.
- inductance of leads and plates leads to
LC

ZE(R)=R, ZE(L)=jwL, ZE(C)=1/(jwC)
Therefore, devices are only simple
under limited conditions outside this range parasitics must be accounted for.
We have frequency effects as above
but also nonlinearity effects e.g. bulbs, diodes etc.
Therefore, to model one must
specify operating conditions and amplitude of voltage and current excursions.
Two possible forms of models:
(1) small signal model - Looking at small signal variations
about Q.
(2) large signal/total - Looking at complete situation.
Diode Modelling
Diode

Diode Operating Characteristic

vD
iD = IS (exp ----- - 1)
nVT
where
VT
= KT/q = 25mV at room temperature.
K = Boltzmann's constant 1.38 x 10-23 J/K
T = Absolute temperature (K) = 273 + oC
q = electron charge 1.602 x 10-19 C
n = device constant between 1 and 2
For IC n=1, and for discrete (high
or low current) n=2.
IS = reverse current
(doubles for every 5o increase in temperature.)
vD
In forward bias iD » IS exp -----
nVT
In reverse bias iD » - IS.



Small Single Diode


VD/nVT
DC ID = IS e
vD/nvT
Instantaneous vD = VD + vd and
iD = IS e
(VD+vd)/nVT vD/nVT vd/nVT
\ iD
= IS e = IS e e
Substitute for ID
vd/nVT
iD
= ID e
If vd is kept small so
that vd/nVT<<1 we can use a series expansion and
retain first two terms
\
iD » ID(1 + vd/nVT)
N.B. general requirement for small
signal behaviour is that second order terms and above in the series expansion
are negligible.
That is
vd
1 vd
----- >> --- ( ----- )2
nVT
2! nVT
\
2nVT >> vd
Assume n = 1 and VT =
25mV
We require vd <<
50mV
i.e. vd of the order of
5mV or so.
ID
\
iD = ID + ----- vd = ID + id - DC + AC component
nVT
ID
id = ----- vd = gdvd = vd/rd
nVT
where gd is the small
signal diode conductance.
rd = 1/gd is the small signal diode
resistance or
incremental resistance
25
N.B. rd º re
= ---------
ID (mA)
Small Signal Diode Model
Replace
diode's nonlinearities by a Taylor's series expansion around Q and only retain
the linear part.
vD
= VQ + vd
iD
= IQ + id

Taylor's series about x = a is
df ¦ 1 d2f ¦
f(x)
= f(x) + ----¦
(x-a) +
--- -----¦
(x-a)2 + ....
dx ¦x=a 2 dx2 ¦x=a
For x near "a" (¦x-a¦<<1) non linear terms can be ignored.
Therefore, for the diode
¦ df
¦
iD = f(vD)¦ + -----¦ (vD - VQ) +
nonlinear terms
¦Q dvD
¦Q
vD
where iD » IS
exp -----
VT
VQ 1 VQ
\
iD = IS exp ---- + ( --- IS exp ---- ) vd + ....
VT VT VT
for vd very small
IQ
IQ
+ id » IQ + ( ---- ) vd
VT
IQ
\
id = ----
vd
VT
vd
25
\
rd = ---- = -------
id
IQ(mA)
High Frequency Small Signal Diode Model
[S & S P157]
Includes capacitive effects
(1) Reverse bias - capacitor CJ due to the wide depletion layer


dqJ
CJ
= ----- _
dv v=VA
K
CJ
= -----------
(V0 + VA)m
CJ0
»
------------
(1+VA/V0)m
where
V0
= depletion layer voltage with zero bias
VA
= voltage between diode terminals
K = constant proportional to area of junction
and
impurity concentration.
m = constant proportional to distribution of
impurity
near junction.
(m
= 1/2 for abrupt junction
= 1/3 for gradual junction [B&B P63]).
N.B. VA is negative
(2) Forward bias - in addition to
CJ we have CD which is due to minority charge storage

25
K
rd
= -------- , CJ = ----------- ,
IQ(mA) (V0+VA)m
CD
= KcIQ
tFIDq
= -------- [B&B P64]
eKT
Kc = Constant
e empirical constant in diode equation º 1 to 2
N.B. VA is positive
[ CJ » 1-5pF, rd » 106W,
CD » 10-100pF]
BJT Modelling
Idealized Cross Section of NPN BJT

Bipolar Junction Transistor Small Signal Model

Summary of Capacitive Considerations
Capacitive effects generally
attributable to:
(1) Coupling and by-pass capacitors.
(2) Internal device
capacitances and strays.
For DC :- f = 0
open
circuit (1) and ignore (2)
For LF :- f less than a few 100Hz
include (1) and ignore (2)
For MF :- a few 100Hz < f <
a few 100KHz
short
circuit (1) and open circuit (2)
use r, h parameter etc.
For HF :- f greater than a few 100KHz
short
circuit (1) and include (2)
use hybrid p for f <fT/3
N.B. for small signals:
Replace independent DC voltage sources by short circuit.
Replace independent DC current source by open circuit.
Neglect strays if XC/R > 10 (see later).
Transistor Models
Used
to facilitate practical understanding and design.
2 main types:
(1)
small signal/linear - limited region of operation;
(2) large signal/nonlinear - use straight line
linear segments.
Assumptions lead to trade off
between complexity and
accuracy versus
"useability" (computer versus manual calculations).
Frequency dependence therefore use
a high or low frequency model as appropriate.
Examples of popular models
include:
BJT - r parameter, h parameter, hybrid p,
FET - y parameter.
Summary of BJT Models
DC :- Forward active.
Simplified Ebers-Moll.

Small Signal - first order e.g. r
parameter (LF & MF)
- h parameter (LF & MF)
- hybrid p
parameter (LF, MF, & HF)
Complete models (small and large
signal)
Ebers-Moll
-+ used for computer
Gummel-Poon
-+ simulation
Low Frequency (LF) Small Signal Models
Assumptions :-
(1)
Transistor operating in linear region around
operating point "Q".
(2) Signal variations are small.
(3)
No distortion occurs.
Small Signal BJT
Forward biased base emitter
junction
vBE/VT
vBE = VBE
+ vbe and iE = IS e
(VBE+vbe)/VT VBE/VT vbe/VT
\
iE = IS e = IS e e
vbe/VT VBE/VT
= IE e where
IE = IS e
If vbe << VT
then we can neglect second order terms from the series expansion (leads to
linear operation).
\
iE » IE (1+vbe/VT)
VT
» 25mV but this small signal
approximation holds if vbe is less than about 10mV.
IE
\
iE = IE + ------ vbe
- DC + AC component
VT
IE
AC component ie = ----- vbe = gmvbe
VT
gm is the
transconductance IE/VT
(= 1/re)
N.B. BJT :- gm
depends on IE and VT.
FET :- gm
depends on Ö(ID) and W/L.
Base Input Resistance rp (first order model)
We have
IC
iC » iE = IC + ---- vbe
VT
IC
IC
iB
= ---- + ----- vbe
b bVT
\
iB = IB + ib
1 IC
i.e. ib = --- ----
vbe but gm » IC/VT
b
VT
gm
\ ib
= ---- vbe
b
Input resistance rp = vbe/ib = b/gm
substitute for gm and
IB = IC/b
rp = VT/IB

¦¦¦

First order models apply to both
npn and pnp without change in polarities.
vbe
= vp
Since output current is gmvp = gm rp ib = b ib
Emitter Resistor re (first order model)
iE
= iC / Á = IE + ie
IC IE
where IE = IC
/ Á
and ie = ----- vbe = ----- vbe
ÁVT VT
vbe
VT
but re = ----- = ----
ie
IE
IE
IC
gm = ---- » ----
VT
VT
\ re »
1/gm
re is base emitter
resistance when looking in at e.
rp is base emitter resistance when
looking in at b.

[It can be shown that rp = (b+1)re ]
BJT Models
Equivalent
Tee (T) or r parameter

Represents a CE amplifier biased in the forward active region (base emitter junction forward
biased and base collector junction
reverse biased).
Whence:-
25
re=
-------- ; resistance of forward biased junction.
IE(mA)
(room temperature 300K)
rc - large resistance of reverse biased junction.
rb - base spreading resistance.
ic = Á0ie
» b ib
where Á0 is LF current gain.
b 1+hfe
Á = ------ rc = -------
1+b hoe
hre hre(1+hfe)
re
= ----- and rb = hie
- ------------
hoe hoe
Some typical values are:-
re = 10 W
rb = 100 W
rc = 1 M W
Á0=
0.99
rb and rc
can often be omitted.
Using the r Parameter Model
Consider
the potential divider emitter resistor circuit shown below

(1) For DC design open circuit all
capacitors.

(a) Ignoring R1 and R2
we have:
Vin
= VBE + VE = VBE + IERE
= IERE if VE>>VBE
Now IE = IB(1+bdc) » bdcIB if bdc>>1
Vin IBbdcRE
\ Rin(base)= ----- =
---------- = bdcRE
Iin IB
(b) with R1 and R2
R2 __
Rin(base)
VB
= ---------------------- VCC
R1 + R2 __ Rin(base)
if bdcRE>>R2
then
R2
VB
» ------- VCC
R1+R2
Other components can be found by
the use of KCL and KVL. For example:
VE
= IERE = VB-VBE
VCE
= VCC-IERE-ICRC
etc.
Or use Thevenin's theorem where
R2
RT
= R1 __ R2 and
VT =
------- VCC
R1+R2
VT
= IBRT + VBE + VE
[circuit is independent of IE
if RE>>RT/bdc]
N.B. used to calculate DC
loadlines.
(2) For AC considerations short
circuit all capacitors and replace the DC source by ground (assuming the
internal resistance » 0)
N.B. without CE and RL

¦¦¦

where R = R1 __ R2
(rb and rc are assumed to be negligible)
vb ie (re+RE)
Rin(base)=
---- » ----------- » b(re+RE)
ib ie/b
Rin
= R __ Rin(base) = R1 __ R2 __ b(re+RE)
Rout
» RC [if rc>>RC]
vc ieRC RC
Av=
---- » - ----------- » - -------
vb
ie(re+RE) re+RE
ic
Ai
= ---- = b
ib
Overall gain is reduced by
potential divider effect i.e.
vc
Rin -RC RC
Avs
= ----- = --------
------- ( x ------- with RL)
vs
Rs+Rin re+RE RC+RL
with emitter by pass capacitor CE:
(1)

Open
circuit to DC, therefore no effect
Short circuit to AC, therefore Av=-RC/re
(2)

DC
bias sees RE1+RE2
AC sees RE1 therefore Av=-RC/(RE1+re)
(3)

DC
bias sees RE1
AC
sees RE1 __ RE2 therefore Av=-RC/((RE1 __ RE2) + re)
re(=25/IC(mA))
is temperature dependent, therefore it must be small in comparison with RE
AC for good stability.
N.B. effect of CE on
BW.
Effect of an AC Load
With CE

RC __
RL
\ Av » - ----------
re
N.B. if RL>>RC Þ RC __ RL »
RC
if RL<<RC Þ RC __ RL<RC (gain smaller with RL)
h Parameter BJT Model
[Nevan P237]
CE input characteristics leads to
vBE = f(iB, vCE)
CE output characteristics leads to
iC = g(iB, vCE)
via a 2-D Taylor series about Q we
obtain the linear approximation:-
¶vBE ¶vBE
vbe
» ------ _ (ib) + ------
_ (vce)
¶iB Q
¶vCE Q
¶iC ¶iC
ic
» ----- _
(ib) + ------ _ (vce)
¶iB Q
¶vCE Q
Two port theory leads to :-
vbe
= h11 ib + h12 vce
ic = h21 ib + h22
vce
where vbe and ic
are dependent variables and vce and ib are independent variables.
For CE amplifier
vbe DvBE
h11
= hie = -----
_ » ------ _
ib
vce=0 DiB
VCEQ
vbe DvBE
h12
= hre = -----
_ » ------ _
vce
ib=0 DvCE
IBQ
ic DiC
h21
= hfe = ----
_ » ------ _
ib
vce=0 DiB
VCEQ
ic DiC
h22
= hoe = -----
_ » ------ _
vce
ib=0 DvCE
IBQ

where hie is CE input
resistance with output shorted,
hre is CE voltage feedback ratio with input open,
hfe is CE forward current gain with output
shorted,
hoe is CE output conductance with input open.
h parameters can be obtained from
characteristic's from data sheets or practical measurements.
The model may often be simplified
by omitting the effects of hre and hoe.
CE h Parameter Determination Using Characteristics

h to r Parameter Conversion
It
can be shown that
re
= hre/hoe
rc
= (hre+1)/hoe
hre
rb
= hie -
----- (1+hfe)
hoe
b = hfe
ic
Á = hfb = ----
ie
Example:
How
significant are hre and hoe in the circuit below?
VCC = 20V, RB
= 2MW, RC = 5KW, hie = 2KW, hre = 10-4, 1/hoe = 100KW and hfe = 100.


- Effect of hoe
the effective collector resistance
is RC'
RC'
= RC __ 1/hoe
For engineering purposes
RC' » RC
if 1/hoe is greater about 10RC
This is easily the case
\
RC' » RC = 5KW
Therefore, little error in
neglecting hoe
- Effect of hre
vce
= icRC' = -hfeibRC'
\ hrevce
= -(hrehfeRC') ib
This is dependent on ib.
Using the source absorption theorem hrevce can be
replaced by an equivalent resistance R
R
= hrehfeRC' = 50W
Therefore, since hie (=2KW) >> 50W,
effect of hre is negligible.
N.B. Generally hrevce
can be replaced by a short circuit if hre
<< hie/hfeRC'
Analysis using the Hybrid h Parameter Model

Medium frequencies, therefore
ignore capacitors (short circuits).
Bias design with capacitors open
circuit as before.
AC equivalent with R = R1 __ R2 and neglecting the effects of hoe
and hre.

Voltage gain
Vo
= - hfeIb (RC __ RL)
Vi
= Ibhie + (1 + hfe)IbRE1
Vo
-hfe (RC __
RL)
\ Avi
= ---- = ----------------------
Vi
(hie + (1 + hfe)RE1)
Current gain
RC
Io
= hfeIb ---------
RC + RL
Vi
= I1R = Ibhie + Ib (1 + hfe)RE1
Also Ii = I1 + Ib
R
\ Ib
= Ii ------------------------
R + hie + (1 + hfe)RE1
Io hfeRCR
\ Ai
= ---- = ------------------------------------
Ii
(R + hie + (1 + hfe)RE1) (RC
+ RL)
Input impedance
By inspection Zin = R __ (hie + (1 + hfe)RE1)
Output impedance
(Set Vs = 0 and look
into the output terminals)
Ib
= 0 \ hfeIb = 0
\
Zo = RC
Hybrid p Model of BJT

By
comparison with the h parameter model it can be shown that
rp
hie = rb + ---------- » rb + rp
1 + rpgm
rp(gm
- gm)
hfe
= ------------- » rpgm
1 + rpgm
rpgm
hre
= ----------- » rpgm » 0
1 + rpgm
hoe
= go + gm + rpgm(gm - gm) » go + rpgmgm » go
(we have assumed that rpgm <<1, gm<<gm and gm<<go)
Rearranging the above
rp = hfe/gm
rb
= hie - rp
rm = rp/hre
go
= hoe - gmhre
25
(
re =
-------- = 1/gm
)
IC(mA)
Another popular representation of
the hybrid p model is shown below.

Determination of Hybrid p Parameters
1 e
(1) gm = ---- = ---- _ IC
_
re
KT
» 40 _ IC
_ at room temperature
(2) b = hfe or hFE
(3) rb'e = bo/gm
(4) rbb' is small
and difficult to evaluate.
If
LF hie is known
rbb'
= hie - rb'e
or
if HF yie is known
rbb'
= 1/Real part (yie)
(5) Cb'c is usually given as Cob, Cobo,
Cc, Ccb etc.
gm
(6) If fT is known
Cb'e = ---- - Cb'c
wT
1
If fb is
known fb = --------------------
2prb'e(Cb'e
+ Cb'c)
can be used.
Analysis using the Hybrid p Model

¦¦¦

AC equivalent with R = R1 __ R2 and neglecting the effects of rb'c
and rce.
At the three nodes we have
VO(GC
+ GL) + gmVb'e = 0 (1)
VE
= (Vb'e gb'e + Vb'e
gm) RE1
(2)
VI
= Vb'e gb'e (rbb' + rb'e)
+ VE
= Vb'e [rbb'
gb'e + 1 + (gb'e + gm) RE1] (3)
Voltage gain Avi
VO -gm
Avi
= ---- = ------------------------------------
VI
[rbb'gb'e + 1 + (gb'e+gm)RE1][GC+GL]
-gm -RC __
RL
»
------------------ » ---------
(1+gmRE1)[GC+GL] RE1
[if
gmRE1>>1, rbb'<<rb'e
and go<<GC+GL]
Input resistance
Ib'e
= Vb'e gb'e and therefore using equation (3)
VIgb'e
=
-----------------------------
rbb'gb'e + 1 + (gb'e+gm)
RE1
VI
=
-----------------------------
rbb'
+ rb'e + (1+gmrb'e)RE1
II
= VIG + Ib'e where G = 1/R
1
\
II = VI [ G + ----------------------------- ]
rbb' + rb'e +
(1+gmrb'e)RE1
But b = gmrb'e
VI
R[rbb' + rb'e + (1+gmrb'e)RE1]
\ Ri
= ---- = ----------------------------------
II
R + rbb' + rb'e + (1+gmrb'e)RE1
= R
__ [rb'e
+ (1+b)RE1]
Current gain Ai
IO
VO Ri -gmGLR rb'e
Ai
= ---- = ---- ---- = -------------------------------
II
VI RL (GC+GL)[R+rbb'+rb'e+(1+b)RE1]
If rbb'<<rb'e and
1<<gmrb'e
-gmGLR rb'e
Ai
= --------------------------
(GC+GL)[R+rb'e(1+gmRE1)]
-gm(RC __ RL)R rb'e
= ---------------------
RL(R+rb'e+bRE1)
Output resistance
With rce omitted Ro»RC
(Assuming rce <<
(GC + GL))
Including the effect of ro on voltage gain
[B&B P450]

Vo(GC
+ GL + gce) = (gce - gm)Vb'e
VE(GE
+ gce) = Vb'e(gb'e + gm) + gceVo
Vi
= Vb'egb'e(rbb' + rb'e) + VE
Combining all three equations
Vo
(gce-gm)(GE+gce)
----=-------------------------------------------------------
Vi (GC+GL+gce)[(GE+gce)gb'e(rbb'+rb'e)+gb'e+gm]+gce(gce-gm)
gce can be neglected if
gce<<(GC+GL) and gce<<GE
and gce<<gm which is usually the case.
Use of Small Signal Transistor Models
(1) Mark B, C, E (or G, D, S) on
the circuit diagram as the start of the equivalent circuit.
(2) Replace each Transistor by its
model.
(3) Transfer all components
(reisitors, capacitors and signal sources) to the equivalent circuit.
(4) We are only interested in
changes around Q, therefore, replace each independent DC source by its internal
resistance.
Ideal voltage source by short
circuit and ideal current source by open circuit.
(5) Apply KVL and KCL as necessary.
Ro is defined with VS
= 0 and RL = Ñ.
[Signal and load resistances
should be included in the analysis as necessary.]
Justification for Using Approximate Circuits
[Comer]
Inaccuracies
can be shown to be quite small ( ~ 5 to 10%). Become even less important in the
light of:
(1) Standard component tolerances
of 5 to 20%, therefore values not accurately known.
(2) Most practical applications
use an unbypassed or partially bypassed RE for good AC stability.
(3) 5 to 10% accuracy is good
enough for most engineering design (?).
For better accuracy precision components are used in circuits that are
designed to depend on component values rather than transistor parameters (feedback
circuits).
(4) Greater accuracy can be
achieved by additional elements, eg. reactive effects at high frequencies.
(5) Manual design work is limited
by the complexity of more accurate models.
(6) Simpler circuits lead to a
better physical feel and understanding of the dominant mechanisms.
(7) Transistor parameters required
for more accurate models are not easily available from data sheets, and only
typical values are usually provided.
Parameters vary widely so designers would need to measure them for each
device.
Therefore, its easier (?) to use simple models in
feedback configurations with accurate resistors etc.
Bode Magnitude and Phase Plots
Decibel

Power gain
P2 ¦ V2I2 ¦
AP
= ---- = ¦------¦ = Av Ai
P1 ¦ V1I1 ¦
AP(dB)
= 10 log10 (P2/P1)
V22R1
= 10 log10 -------
V12R2
= 20 log10 ¦ V2/V1 ¦ + 10 log10 ¦R1/R2¦
AP(dB) = 20 log10 ¦ V2/V1 ¦ (if R1=R2)
= 20 log10 ¦ I2/I1 ¦ (if R1=R2)
\ Av(dB)
= 20log10 ¦ V2/V1¦
Notes - 0dB is often used as a reference
- half power
condition - the frequency at which
Ap = Apm/2
i.e. Ap(dB) = 10log10 (0.5) = -3dB
this is the same frequency as that at which
Av = 0.707 Avm
i.e. Av(dB) = 20log10 (0.707)= -3dB
- dBm decibels
relative to 1mW
i.e. 1mW = 0dBm.
(e.g. 2mW power = +3dBm
0.5mW power = -3dBm).
Transfer Functions
Consider a network of the form
shown below:

The transfer function for the
network can be defined as follows:
V2
H(jw) = ---- (jw)
V1
or
V2
H(S)
= ----
(S) [S=s+jw]
V1
Cascaded Amplifiers

j(q1+q2+q3+ ... +qn)
Av
= ¦A1 A2 A3
... An¦ e
\ Av(dB)
= 20log¦A1¦ + 20log¦A2¦ + ... + 20log¦An¦
qv = q1 + q2 + q3 + ... + qn
High Pass Filter (Series Capacitor)
[Bogart P370]

V2 1
H(jw) = ----
(jw) = ---------- [wc = 1/RC]
V1 1-jwc/w
1
\ fc
= ------
2pRC
1
\ ¦ H(jw)¦ = --------------
Ö(1+(wc/w)2)
qL(jw) = tan-1 (wc/w)
Magnitude Response

Phase Response

1
Exact response for H(jw) = ---------
1-jwc/w
20log[1+(wc/w)2]-1/2
q(jw)=tan-1(wc/w)
w (dB) (degree)
------------------------------------------------------
0 -Ñ 90.0
0.1wc -20.04
84.3
0.5wc -6.99
63.4
wc -3.01 45.0
5wc -0.17 11.3
10wc -0.0432 5.7
Ñ 0 0
[Bogart P370]
More generally for a circuit with
Source
resistance rs
Input
resistance ri
Input
series capacitance Cis
Load
resistance rL
Output
resistance ro
Output
series capacitance Cos
Then corner frequency due to Cis
is
1
fCis
= --------------
2pCis(rs+ri)
Corner frequency due to Cos
is
1
fCos
= --------------
2pCos(ro+rL)
High Pass Filter Response


[Millman P385]
N.B.
t
= RC
fL
= %
sag * fp/p
where fp is frequency
of the pulse waveform.
Low Pass Filter (Shunt Capacitor)

V2 1
H(jw) = ----
(jw) = --------- [wc = 1/RC]
V1 1+jw/wc
1
\ fc
= ------
2pRC
1
\ ¦ H(jw)¦ = --------------
Ö(1+(w/wc)2)
qH(jw) = -tan-1 (w/wc)
Magnitude Response

Phase Response

1
Exact response for H(jw)
= ---------
1+jw/wc
20log[1+(w/wc)2]-1/2 q(jw)=-tan-1(w/wc)
w (dB) (degree)
------------------------------------------------------
0 0 0
0.1wc -0.0432
-5.7
0.5wc -0.969
-26.6
wc -3.01 -45.0
5wc -14.15 -78.7
10wc -20.04
-84.3
Ñ -Ñ -90.0
More generally for a circuit with
Source
resistance rs
Input
resistance ri
Input
shunt capacitance Cip
Load
resistance rL
Output
resistance ro
Output
shunt capacitance Cop
Then corner frequency due to Cip
is
1
fCip
= -----------------
2pCip(rs
__ ri)
Corner frequency due to Cop
is
1
fCop
= -----------------
2pCop(ro
__ rL)
Low Pass Filter Step Response


N.B. t = RC
Proof that fH = 0.35/tr
tr is the time required
for a voltage to rise from 10% to 90% of its final value VF. Where v is given by
v
= VF(1-exp(-t/(RC)))
when v = 0.1VF
0.1VF
= VF(1-exp(-t/(RC)))
0.9
= exp(-t/RC)
ln
[exp(-t/(RC))] = ln 0.9
\
t = 0.1RC
Similar analysis with v = 0.9VF
gives
t
= 2.3RC
\
tr = 2.3RC - 0.1RC = 2.2RC
Critical frequency for RC network
is RC = 1/2pfH
2.2 0.35
\
tr = ------ = ------
2pfH fH
N.B.
(1) Corner frequency found in both
cases by substituting
¦ H(jw) ¦ = 1/Ö2
(2) Overall multiple stage
(section) response is determined by adding in the effect of the individuals.
(3) Special care must be exercised
at break/corner frequencies wc, 10wc and wc/10 for each stage (section).
(4) Gain falls at 20dB/dec at wc
phase falls at 45o/dec
at 0.1wc
General Frequency Effects (BJTs)
(1) Low frequencies - ignoring
HFs.
High-pass filter effects due to:
- input coupling capacitance CI
- output coupling capacitance CO
- emitter by-pass capacitance CE (if present).

1
fCIL=
------------------
rin'» R1 __ R2 __
bre
2p(rin'
+ rs')CIL
1
fCOL=
---------------- ro'= rce __ RC » RC
2p(ro'+
RL)COL
1
rs'
__ R
fCE=
------- Re=RE __ [
---------- + re
]
2pReCE b
(Am» -gm(RC __ RL)) (R= R1 __
R2)
(2) High frequencies - ignoring
LFs.
Low-pass filter effects due to:
shunt capacitances to ground; wiring; solder joints;
coupling from other devices; internal transistor
capacitances.

1
fCIH=
--------------------
CIH=CWLI+Cb'e+Cb'c(1-Am)
2p(rs' __ rin')CIH
rin'» R1 __
R2 __ bRe
1
fCOH= ------------------- COH=
CWLO + Cb'C
2p(ro' __ RL) COH
ro'= rce __ RC (»RC)
Am» -gm(RC __ RL)
(3) High frequency effect due to
unity gain frequency fT
[B&B P493]
Unity Gain Frequency fT
is used to characterise a transistor's frequency capability. fT is
obtained using a circuit of the form:

¦¦¦

rbb' and rb'c
have been neglected.
Vb'e
= Is (rb'e __ XC __
XC )
b'e
b'c
1
rb'e ( --------------- )
jw(Cb'e+Cb'c)
=
----------------------------- Is
1
rb'e
+ ---------------
jw(Cb'e+Cb'c)
rb'e
=
-------------------------- Is
1 + jwrb'e(Cb'e
+ Cb'c)
If we neglect the forward current
through Cb'c
Io
» gm Vb'e
Using this along with b0 = gm
rb'e
Io gm rb'e
---- (jw) = b(jw) =
-----------------------
Is 1 + jwrb'e(Cb'e+Cb'c)
b0
=
-------------------------
1 + jw(Cb'e+Cb'c)b0/gm
We can best understand this by
considering the following plot of CE and CB gains for short circuit output.

wT » b0wb
or fT = b0fb
Gain bandwidth product fT
= b0fb
Therefore, the LF asymptote is b0 and the 3dB corner frequency is
gm
wc = wb = 2pfb = -----------------
b0(Cb'e
+ Cb'c)
(wb is the b cut off frequency)
By setting ¦b(jw)¦ = 1 we obtain the unity gain frequency
gm gm
wT = 2pfT = --------------- = ---------
(Cb'e + Cb'c) (Cp+Cm)
Typical Variations of fT Versus IE and VCE

Illustration of Capacitance Effects on Frequency Response

Response Curve Illustrating Bandwidth

Simplified Response Curve
Where fol is negligible
compared to foh

Selection of Corner Frequency
Interaction or not?
LF:- Low frequency options using fCE to dominate
-
fCE=fL, fCI=fL/10, fCO=fL/100
-
20dB/dec each.
-
fCE=fL, fCI=fCO=fL/10
-
20dB/dec at fCE
-
40dB/dec at fCI
-
fCE=fCI=fCO=fL
-
60 dB/dec at fCE
-
fC=(fCE2+fCI2+fCO2)1/2
fCE used because it
results in smaller values of capacitance.
HF:- Less control but
may use RS, RC, RL, Rin etc.
Effect of wT.
Phase Response Overview (CE)
[M&M]
LF : contribution of up to 90o
for each of the poles due to CIL, COL and CE
if they are present.
Midband : phase shift should be 180o